The line with equation x + y = 0 coincides with the terminal side of an angle θ in standard position in quadrant ii .

what is the value of tanθ ?

tanθ = -1

m=tanθ = -1

Step-by-step explanation:

Step 1:-

using formula m=tanθ

Given straight line is x+y=0

The given straight line is passing through the origin so y = -x

straight line is passing through the origin so y = m x

m = -1

Step3:-

The line with equation x+y=0 with the terminal side of an angle θ in standard position in Quadrant II i.e., θ = 90+45=135

 m  = tanθ

 m  = tan(90+45)

  m   = - cot 45

   m   = -1

Step4:-  m =tanθ =-1

the answer is mp

step-by-step explanation:

(a) {a₁, a₁r, a₁r², … a₁rⁿ⁻¹, …}

(b) $59 398

step-by-step explanation:

(a) the annual sequence of profits

aₙ = a₁rⁿ⁻¹

the model for the sequence of profits is {a₁, a₁r, a₁r², … a₁rⁿ⁻¹, …} .

(b) profit after 15 yr

  a₁ = $ 30 000

  r = 1.05

a₁₅ = 30 000 × 1.05¹⁴

a₁₅ = 30 000 × 1.979 93

a₁₅ = $59 398

the profit in year 15 will be $59 398.