Me with these two questions. and can you tell me how to do this! you

(X-10)(X-10) You need to first multiply out the brackets. So, first times X by X, which makes x^2 . Then do -10 x -10 which makes 100. You then need to multiply the X within the first bracket with the minus 10 in the second bracket which makes -10x. Do the same but with the -10 from the first bracket and the X from the second which again makes -10x. So altogether you have x^2-10x-10x+100. This can be simplified down to x^2-20x+100. You then do the same thing for the second question :)

(x-10)(x-10) = (x-10)^2 so in this case just you need to know formula of 

(a-b)^2 = a^2 -2ab +b^2

use please this and so will get the right answer sure 

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12