Use the figure below to complete the following problem. given: h = 2x + 60 t = x + 30 halt is a ∠h = 90 120 150

∠H = 120

Step-by-step explanation:

See the attached figure

HALT is a parallelogram

So, angles H and T are supplementary.

∠H = 2x + 60  and ∠T = x + 30

∠H + ∠T = 180

∴ 2x + 60 + x + 30 = 180

∴ 3x + 90 = 180

∴ 3x = 180 - 90 = 90

∴ x = 90/3 = 30

So, ∠H = 2x + 60 = 2 * 30 + 60 = 60 + 60 = 120

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form