Aboy has 3 red , 6 yellow and 5 green marbles. in how many ways can the boy arrange the marbles in a line if: all marbles have different sizes?

8.72*10^10

Step-by-step explanation:

Total number of balls = 14

Now,

Make 14 lines.

_ _ _ _ _ _ _ _ _ _ _ _ _ _

In the first position, you can choose any ball from 14 balls. So,

14 _ _ _ _ _ _ _ _ _ _ _ _ _

In the second position, you can choose any ball from 13 balls. This is because you've already kept one ball in first position. So,

14 13 _ _ _ _ _ _ _ _ _ _ _ _

In the third position, you can choose any ball from 12 balls. So,

14 13 12 _ _ _ _ _ _ _ _ _ _ _

Do this until you fill all the place.

14 13 12 11 10 9 8 7 6 5 4 3 2 1

Multiply all of this.

14 *13 *12 *11 *10 *9 *8 *7 *6 *5 *4 *3 *2 *1

= 8.72*10^10

binomial distribution

median= 2

range = 7-0 = 7

how to find median?

no. of term=28

median=(28+1)/2=14.5th term

the 14th and 15th term are 2, therefore the median is (2+2)/2 = 2

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)