Abox contains 5 plain pencils and 5 pens. a second box contains 3 pencils and 1 crayon. one item from each box is chosen at random what is the probability that a pen from the first box and a crayon from the second box are selected

0.75

Step-by-step explanation:

OK maths is always about looking at thing simply, one by one.

Let us look at the first box. There r 5 pencils and 5 pens. So what is the probability of getting a pen from first box? First there r total of 10 things in the first box. Probability of getting a pen from that box? It is 5÷10 which is number of favorable pitcomes to pen ÷ total number of outcomes which is 10.

Now the second box. There r 1 crayon and 3 pencils. Total of 4 outcomes(3plus1).

So probablilty of getting a crayon from second box is number of favorable outcomes to crayon ÷ total number of outcomes which is 4=1÷4

Now add the first probability of getting a pen from first box and probability of getting a crayon from second box. This is because it's given in the question to find out the probability of getting a pen AND a crayon which means first find the probability of pen and crayon seperatly and then add them.

Now add those 2 probabilities together which is 5÷10 plus 1÷4 then we will get 0.75.

I hope this helps u. Pls follow me and like it.

3432532

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!