Acoin is tossed 4 times. what is the probability if getting 2 heads, 2 tails?

11/16

Step-by-step explanation:

P(THHH)=4!3!∗(12)4=416P

(THHH)=4!3!∗(12)4=416, we are multiplying by 4!/3! since THHH scenario can occur in number of ways: THHH, HTHH , HHTH, or HHHT (notice that 4!/3! basically gives number of arrangements of 4 letters THHH out of which 3 H's are identcal).

P(T≥2)=1−(1/16+4/16)=11/16

r and t.

both are 64 degrees.

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!