The probability that an american company will open a location in shanghai, china is 0.7. the probability that it will open a location in beijing, china is 0.4. the probability that it will open a location in either shanghai or beijing or both is 0.8. what is the probability that the company will open a location in:
(a) both shanghai and beijing?
(b) neither shanghai nor beijing?
(c) beijing but not in shanghai?
(d) shanghai given that it opens a location in beijing?

Step-by-step explanation:

Given that the probability that an American company will open a location in Shanghai, China is 0.7.

The probability that it will open a location in Beijing, China is 0.4.

The probability that it will open a location in either Shanghai or Beijing or both is 0.8.

the probability that the company will open a location in:

(a) both Shanghai and Beijing :

P(both) = 0.3

(using addition theory of probability for union of sets)

(b) neither Shanghai nor Beijing

= 1- P(AUB)

(c) Beijing but not in Shanghai?

P(Beiging)_P(both) =

(d) Shanghai given that it opens a location in Beijing

=P(Both)/P(Beijing) =

answer are

step-by-step explanation:

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it