Anewspaper carrier has $3.65 in change he has four more quarters then dimes but two times as many nickels as quarters how many coins of each type does he have

The number of quarter coins is 9, the number of dime coins is 5 and the number of nickel coins is 18

Step-by-step explanation:

Let

x ----> the number of quarter coins

y ---> the number of dime coins

z ---> the number of nickel coins

Remember that

we know that

----> equation A

----> equation B

----> equation C

Solve the system by substitution

substitute equation B and equation C in equation A

solve for x

Find the value of y

substitute the value of x

Find the value of z

therefore

The number of quarter coins is 9, the number of dime coins is 5 and the number of nickel coins is 18

it 2

step-by-step explanation:

8^1/3=2