Aschool is having a valentine's day sale. the first day, they sold 20 roses and 15 boxes of chocolate for $80. the second day they sold 40 roses and 20 boxes of chocolate for $120. how much were the roses and how much were the boxes of chocolate?

roses were $1 each and chocolates were $4 per box

Step-by-step explanation:

let Cost of 1 rose = "R" and Cost of 1 box of chocolate = "C"

First day: cost of 20 roses + cost of 15 chocolate = $80,

or...

20R + 15C = 80  (divide both sides by 5)

4R + 3C = 16 (eq 1)

Second day: cost of 40 roses + cost of 20 chocolate = $120,

or...

40R + 20C = 120  (divide both sides by 10)

4R + 2C = 12 (eq 2)

by elimination, (eq 1) - (eq 2)

(4R + 3C) - (4R + 2C) = 16 - 12

4R + 3C - 4R - 2C = 4

C = 4  (substitute this back into eq 1)

4R + 3(4) = 16

4R + 12 = 16

4R = 16 - 12

4R = 4

R = 1

Hence roses were $1 each and chocolates were $4 per box

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation: