You have 2 different savings accounts. for account a, the simple interest earned after 9 months is $6.94. for account b, the simple interest earned after 18 months is $13.80. if the interest rate is 3.7% for account a and 2.3% for account b, how much is the principal in each account? which account earned you the most interest the first month? explain your answer.

Step-by-step explanation:

The formula for simple interest is expressed as

I = PRT/100

Where

P represents the principal or initial amount of money invested.

R represents interest rate

T represents time

Considering the investment on account A,

I = $6.94

R = 3.7%

T = 9 months = 9/12 = 0.75 years

6.94 = (P × 3.7 × 0.75)/100 = 0.02775P

P = 6.94/0.02775 = $250

Considering the investment on account B,

I = $13.80

R = 2.3%

T = 18 months = 18/12 = 1.5 years

13.8 = (P × 2.3 × 1.5)/100 = 0.0345P

P = 13.8/0.0345 = $400

To determine the account that earned more interest in the first month,

250/9 = $27.8

400/18 = $22.2

Account A earned you the most interest the first month because $27.8 is higher than $22.2

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!

i need more details sorry

step-by-step explanation: