Prove using algebra that the difference between the squares of consecutive odd numbers is always a multiple of 8.
let 2n+1 be the smaller of the two odd numbers.

in steps

Step-by-step explanation:

(2n+3)² - (2n+1)² = 4n² + 12n + 9 - 4n² -4n - 1

= 8n + 8 = 8 (n + 1)  ... always multiple of 8

welll its a very hard question but ill

step-by-step explanation:

first you take the 6 dollars and add 10 to it then add the 50 to that then multiply by 8 with xy and your answer will be

hope this