It seems logical that restaurant chains with more units (restaurants) would have greater sales. ca 5 n we predict sales by measuring a restaurant chain's number of units? presented below are data from nine large restaurant chains. use the accompanying scatterplot, correlation matrix and simple linear regression output to answer the question that follows the output. number of units in thousands sales in billions chain mcdonald's burger king taco bell pizza hut wendy's kfc subway dairy queen hardee's 12.4 7.5 6.8 8.7 4.6 5.1 11.2 5.1 2.9 17.1 7.9 4.8 4.7 4.6 2.9 2.7 2.7 12 10 6 2.5 75 10 12.515 175 units (x) units () sales (y units (x sales (y) 0.636126 regression statistics 0.636125902 0.404656163 0.319607043 2 601614486 multiple r square adjusted r square standard error observations anova df ms 32.20343668 32.20343668 4.75791125 0.065518364 regression residual total 47.37878554 6.768397935 8 79.58 p-value lower 95% upper 95% lower 95 0% upper 95096 4.633131413 1441374831 3.214383458 0.014767988 1.224821532 8 041441294 1.224821532 8.041441294 0.439724072 0.201591433 2.181263682 0.065518364 -0.03696392 0.916412063 003696392 0.916412063 coefficients standard error stat intercept units (x) the correct regression equation to predict sales based on units, according to this analysis, is.. sales 4.63+0.44(units) sales 4.63-0.44(units) sales = 0.44 + 4.63(units) sales 0.44- 4.63(units)

Step-by-step explanation:

Hello!

A regression model was estimated in order to test if the number of units of a restaurant chain affecta the sales of said restaurant chains.

The estimated model is:

Y= a + bX

Where

Y: is the sales of a restaurant chain

X: number of units of a restaurant chain

Looking at the computed data, the estimated coefficients are:

a= 4.633131413

b= 0.439724072

The correct regression equation to predict Sales based on Units, according to this analysis, is..

Y= 4.63 + 0.44X

I hope it helps!

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation: