What is the exact value of arcsin(−√2/2) ?

enter your answer, in terms of π , in the box.

5Π/4

Step-by-step explanation:

arcsin(−√2/2) = -45°

Note that the angle is negative and according to quadrant, sine is negative at the 3rd and 4th quadrant.

In the 3rd quadrant, the equivalent angle is (180+theta) while at the 4th quadrant it is (360-theta.)

Using the 3rd quadrant which will give us the least value,

theta = 180+45

= 225° (note that the minus sign only tells us the quadrant sine falls into, hence we cant use the minus during addition)

therefore theta = 225°

Since 180° = Πrad

225° to rad = 225×Πrad/180

= 5Π/4 rad

answer:  

step-by-step explanation:

here x represents the height of the pole,

and, the height of the shadow of the pole is 12 feet.

also, the angle of elevation from the top of the pole is 40°,

therefore,

by the low of sine,

which is the required equation for finding the value of x,

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )