Saurav sold two radios for rs. 1200 and rs. 1350 respectively. he made a profit of 20% on the first radio and 2% profit on the whole. what was the loss percentage on the second radio ?

Step-by-step explanation:

total sold amount= 1200+1350=2550

profit amount on first radio= 1200-(1200/1.2)=1000

purchase amount of 1st radio= Rs. 1000

total purchased amount= (2550/1.02) = Rs. 2500

purchase amount of second radio=  2500 - 1000 = Rs. 1500

loss % on second radio= ((1500-1350)/1500 ) * 100 = 10%

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

answer: the anser is 3

step-by-step explanation:

c- 2o is equal to 9