The prime polynomial or an irreducible polynomial is
i.e.,
.
Further explanation:
In the question it is asked to choose the option which correctly signifies a prime polynomial.
The options are as follows:
Option A: ![x^{3}+3x^{2}+2x+6](/tpl/images/0330/9789/abf95.png)
Option B: ![x^{3}+3x^{2}-2x-6](/tpl/images/0330/9789/70206.png)
Option C: ![10x^{2}-5x+4x+6](/tpl/images/0330/9789/fbe85.png)
Option D: ![10x^{2}-10x+6x-6](/tpl/images/0330/9789/4edd1.png)
A number which cannot be further factorized into the product of its factors is called a prime number. Just like a prime number there exists a prime polynomial.
A prime polynomial is also called as an irreducible polynomial.
An irreducible polynomial is a polynomial which cannot be expressed as product of its factors or a polynomial which cannot be factored into a polynomial of lower degree.
Option A:
In option A the polynomial is given as
.
Consider the function as follows:
![F(x)= x^{3}+3x^{2}+2x+6](/tpl/images/0330/9789/b57a9.png)
Substitute
for
in the above equation.
![\begin{aligned}F(-3)&= (-3)^{3}+3(-3)^{2}+2(-3)+6\\&=-27+27-6+6\\&=0\end{aligned}](/tpl/images/0330/9789/fe736.png)
Therefore, the value of
is
.
As per the factor theorem
is a factor of the polynomial
.
Therefore, the polynomial
has a factor as
so, the polynomial given in the option A is not a prime polynomial.
This implies that option A is incorrect.
Option B:
In option B the polynomial is given as
.
Consider the function as follows:
![F(x)= x^{3}+3x^{2}-2x-6](/tpl/images/0330/9789/30c85.png)
Substitute
for
in the above equation.
![\begin{aligned}F(-3)&= (-3)^{3}+3(-3)^{2}-2(-3)-6\\&=-27+27+6-6\\&=0\end{aligned}](/tpl/images/0330/9789/989d7.png)
Therefore, the value of
is
.
As per the factor theorem
is a factor of the polynomial
.
Therefore, the polynomial
has a factor as
so, the polynomial given in the option B is not a prime polynomial.
This implies that option B is incorrect.
Option C:
In option C the polynomial is given as
.
Consider the function as follows:
![F(x)= 10x^{2}-4x+3x+6](/tpl/images/0330/9789/52d52.png)
Simplify the above expression as follows:
![\begin{aligned}F(x)&= 10x^{2}-4x+3x+6\\&=10x^{2}-x+6\end{aligned}](/tpl/images/0330/9789/7b2fb.png)
For the above function the degree or the highest power of the variable is
. This implies that the above function is a quadratic function.
A quadratic function is a function in which the degree or the highest power of the variable is
.
The general form of a quadratic function is as follows:
![\fbox{\begin\\\ \math F(x)=ax^{2}+bx+c\\\end{minispace}}](/tpl/images/0330/9789/2d748.png)
The discriminant of the above function is calculated as follows:
![\fbox{\begin\\\ \math D=b^{2}-4ac\\\end{minispace}}](/tpl/images/0330/9789/385c0.png)
The quadratic function obtained above is as follows:
![F(x)= 10x^{2}-x+6](/tpl/images/0330/9789/357d2.png)
The discriminant of the above function is calculated as follows:
![\begin{aligned}D&=(-1)^{2}-(4\times 10\times 6)\\&=1-240\\&=-239\end{aligned}](/tpl/images/0330/9789/cfaf6.png)
Since the discriminant is negative this means that there are no real roots of the function.
Since, the roots of the function are imaginary so, the function
does not have any factor which would give a real root.
From the above statement it is concluded that the polynomial
is a prime polynomial.
This implies that option C is correct.
Option D:
In option D the polynomial is given as
.
Consider the function as follows:
![F(x)= 10x^{2}-10x+6x-6](/tpl/images/0330/9789/951a4.png)
Simplify the above expression as follows:
![\begin{aligned}F(x)&=10x^{2}-10x+6x-6\\&=10x(x-1)+6(x-1)\\&=(x-1)(10x+6)\end{aligned}](/tpl/images/0330/9789/09190.png)
From the above calculation it is concluded that the function
is factored as
.
Therefore, the polynomial
in not a prime polynomial.
This implies that option D is incorrect.
Thus, the prime polynomial or an irreducible polynomial is
i.e.,
.
Learn more:
1.A problem on composite function
2.A problem to find radius and center of circle
3.A problem to determine intercepts of a line
Answer details:
Grade: High school
Subject: Mathematics
Chapter: Polynomial
Keywords: Polynomial, prime, prime polynomial, irreducible, irreducible polynomial, functions, factor, factor theorem, factorize, 10x2-5x+4x+6, quadratic, quadratic function, discriminant.