An isosceles triangle (two sides equal) is placed on top of a square as shown in the picture. if the two equal sides of the triangle are 25m 25⁢m long and the square is 33m 33⁢m on each side, what is the perimeter of the figure?

The perimeter of figure is 215 meters .

Step-by-step explanation:

Given as :

An isosceles triangle (two sides equal) is placed on top of a square

The measure of each side of square = 33 meters

The measure of same two sides of isosceles triangle = 25 m

From figure

ABCD is a square with sides

AB = BC = CD = DA = 33 m

And

CDE is a isosceles triangle with sides

CD = 33 m

CE = ED = 25 m

Let The perimeter of figure = x meters

Again

The perimeter of figure = Perimeter of square + Perimeter of Triangle

∵ Perimeter of square = 4 × sides

So, Perimeter of square = 4 × 33 m

Or, Perimeter of square = 132 meters

And

∵ Perimeter of triangle = sum of measure of all sides

So, Perimeter of triangle = CD + DE + EC

Or, Perimeter of triangle = 33 m + 25 m + 25 m

Or, Perimeter of triangle = 83 meters

Now, The perimeter of figure = Perimeter of square + Perimeter of Triangle

So, x = 132 meters + 83 meters

Or, x = 215 meters

So, The Perimeter of figure = x = 215 meters

Hence, The perimeter of figure is 215 meters . Answer

mark other person brainliest

maximum area = xy = (16)(32) = 512 ft2

to maximize the area of the garden, the side of the fence parallel to the side of the house should be 32 ft long, and the other two sides should both have length 16 ft.'

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