Each afternoon maria walks the dogs at a local pet shelter for up to 2 hours. maria spends 16 minutes walking a large dog and 12 minutes walking a small dog. write an inequality for this situation. if maria walked 9 dogs in one afternoon, what is the greatest number of large dogs that she could have walked that afternoon?

is the inequality that represents this situation

The greatest number of large dogs that she could have walked that afternoon is 3

Solution:

Each afternoon maria walks the dogs at a local pet shelter for up to 2 hours

Maria spends 16 minutes walking a large dog and 12 minutes walking a small dog

To find: Inequality for this situation

Let "x" be the number of large dogs taken for walking

Let "y" be the number of small dogs taken for walking

Total time spend = 2 hours = 120 minutes

Time spent for large dog = 16 minutes

Time spent for small dog = 12 minutes

Therefore, a inequality is framed as:

number of large dog x Time spent for large dog + number of small dogs x Time spent for small dog Total time spend

Here we used "less than or equal to" , since total time spend is up to 2 hours

Thus the inequality is found

If maria walked 9 dogs in one afternoon, what is the greatest number of large dogs that she could have walked that afternoon?

So total dogs = 9

number of large dogs + number of small dogs = 9

x + y = 9

y = 9 - x --- eqn 1

Substitute eqn 1 into inequality

Thus the greatest number of large dogs that she could have walked that afternoon is 3

the one that has a slope of 1/2 and is positive.

step-by-step explanation: 2 buckets 1 trip ; 4 buckets 2 trips and so on.

answer: 7. if the functions had a negative leading coefficient and is of even degree, which statement about the graph is true?

step-by-step explanation: