Population growth the population p (in thousands) of oriando, florida from 1980 through 2009 can be modeled by p = 788e0.0248t
where t = 0 corresponds to 1980.
(a) what was the population of phoenix in 2009?
(b) in what year will phoenix have a population of 2,000,000?

(a). 1,617,599

(b). In year 2018.

Step-by-step explanation:

We have been given that population P (in thousands) of Phoenix, Arizona from 1980 through 2009 can be modeled by , where, corresponds to 1980.

(a). To find the population of Phoenix in 2009, we will substitute in our given equation as:

Since our given population is in thousands, so we will multiply 1617.5987731991356 by 1,000 as:

Therefore, the population of Phoenix would be 1,617,599 in 2009.

(b). To find the time, when Phoenix have a population of 2,000,000, we can set an equation as:

We will substitute 2,000 as our given equation represents population in thousands.

Let us solve for t.

Now, we will use natural log to solve for t as:

Now, we need to find 38 years after 1980 that is .

Therefore, in 2018 Phoenix will have a population of 2,000,000.