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the equations x -2 y = 1, 3 x - y = -1, x + 2 y = -1, and 3 x + y = 1 are shown on the graph below.

⊕image below!

which system of equations has a solution of approximately (0.6, –0.8)?
x + 2 y = - 1 and 3 x + y = 1
x - 2 y = 1 and 3 x + y = 1
x -2 y = 1 and 3 x -y = -1
x + 2 y = - 1 and 3 x-y = -1

x + 2 y = - 1 and 3 x + y = 1

Step-by-step explanation:

See the graph attached.

From this graph, it is clear that the green line and the Purple line intersect each other at an approximate point (0.6, -0.8).

Now, the green line passes through the x-intercept (-1,0) and y-intercept (0,-0.5).

Therefore, the equation of the green line will be

⇒ x + 2y = - 1

Therefore, the first combination or the fourth combination will be the answer.

Again, the purple line passes through the point (0,1) and has a negative slope.

So, the equation of purple line will be 3x + y = 1 {Since it has negative slope}

Therefore, the first combination will be the answer.

180

step-by-step explanation:

12-2=10

20-2=18

18x10=180

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!