Drug reaction the intensity of the reaction to a certain drug, in appropriate units, is given by
r(t)=te-0.1t,
where t is time (in hours) after the drug is administered. find the average intensity during the following hours.
a. second hour
b. tewlth hour
c. twenty-fourth hour.

a) A=0.86

b) A=2.81

c) A=2.88

Step-by-step explanation:

The average of a functions can be written as:

(1)

a.) The second hour means that the interval of time is from 0 to 2 hours, so a=0 and b=2. Using the equation (1) we can calculate the average intensity.

Using integration by parts we can solve it.

,

,

(2)

Therefore, the average intensity at the second hour will be:

b) We can use the equation (2) to solve it. In this case the limits of integration will be a = 0 and b = 12 hours.  

Therefore, the average intensity at the twelfth hour will be:

c) Finally, here a = 0 and b = 24 hour.

Therefore, the average intensity at the twenty-fourth hour will be:

I hope it helps you!

4 packs of water and 7 packs of candy bars

step-by-step explanation:

35x4=140

140/20=7

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.