Finding an equation of a tangent line in exercise, find an equation of the tangent line to the graph of the function at the given point.
y = x^2 e^-x, (1,1/e)

Equation of tangent will be

Step-by-step explanation:

We have given the function

We have to find the equation of tangent at the point

Equation of tangent is equal to

So

Now we have given point

So putting these points in the equation of tangent

Now equation of tangent passing through

1)is not similar since corresponding sides are not in the same ratio

2)are similar since corresponding sides are in the same ratio and corresponding angles are equal

hope it will

#faazmessi

yes

step-by-step explanation:

yes