What is the area of the figure composed of a parallelogram, a square, and a rectangle?
10 in.
3.5 in.
in
12.5 in.

126 in²

Step-by-step explanation:

Paralelogram's area:

A = 10×3.5 = 35 in²

Square's area:

A = 4² = 16 in²

Rectangle's area:

A = 12.5 × 6 = 75 in²

Total area:

75 + 16 + 35 = 126 in²

I hope I've helped you.

the first dot plot best represents the data

plzplzplzplz mark brainliest and have a good day

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3