Find the angle measuments of a triagle in which one angle measures 10 degress less than twice the second triangle, and the third angle measures 25 degrees more than the second angle.

the first angle is 72.5 degrees.

The second angle is 41.25 degrees.

The third angle is 66.25 degrees

Step-by-step explanation:

Let x represent the size of the first angle.

Let y represent the size of the second angle.

Let y represent the size of the second angle.

one angle measures 10 degress less than twice the second triangle. This means that

x = 2y - 10

the third angle measures 25 degrees more than the second angle. This means that

z = y + 25

The sum of the angles in a triangle is 180 degrees. This means that

x + y + z = 180 - - - - - - - - - - 1

Substituting x = 2y - 10 and z = y + 25 into 1, it becomes

2y - 10 + y + y + 25 = 180

4y + 15 = 180

4y = 180 - 15 = 165

y = 165/4 = 41.25 degrees

x = 2y - 10 = 41.25 × 2 - 10 = 72.5 degrees

z = x + 25 = 41.25 + 25 = 66.25 degrees

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

horizontal translation of 2 units in the positive x direction

followed by

vertical translation of 3 units in the positive y direction