Solve each system of equations
x^2+y^2+18x+29=0
x+y=1

two solutions : (-3;4)  and (-5;6)

Step-by-step explanation:

hello :

X²+y²+18x+29=0    ..(1)

X+y=1 ...(2)

by (2) : y = 1 - x

put this value in (1) : x² +(1-x)² +18x+29 = 0

x² +1 +x² -2x+18x +29 =0

2x²+16x +30 = 0

x²+8x+15 =0

delta = b²-4ac     a=1   b=8   c = 15

delta = (8)²-4(1)(15)=64-60 =4 = 2²

X1=(-8+2)/2 = - 3

X2=(-8-2)/2 = - 5

case 1 : x = -3    y = 1 - (-3) = 4

case 2 : x = -5    y = 1 - (-5) = 6

im alright what do you need

step-by-step explanation:

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b