Isaiah plans to empty his swimming pool by draining it at a rate if 25 gallons per minute. if the cylinderical pool measures 35 feet across in diameter and 6 feet deep, how long will it take to empty isaiahs pool (there are 7.5 gallons in a cubic foot)?

29hours.

Step-by-step explanation:

Volume of a cylinder = πr²h, where π = a constant = 3.142, r = d/2 = 35/2ft because 2r = d and the length or depth = 6ft.

Now, substitute for the values in the formula above,

V = 3.142 x (35/2)² x 6

= 5,773.425ft³.

Since there are 7.5 gallons per ft³,

It implies that 5,773.425ft³

= 5,773.425 x 7.5 gallons

= 43,300.6875gallons.

Draining Rate = 25gallons per minute,

Therefore, 43,300.6875gallons

= (43,300.6875)

25

= 1,732.0275minutes

Convert to hours bearing in mind that ,

60minutes = 1hour

Therefore,

1,732.0275minutes = 1,732.0275/60

= 28.867125hrs.

= 28.87hours

To the nearest hour,

= 29hours.

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