7. photography francine has a camera in which the dista
1 francine has a camera in which the distance from the lens to the film
is 24 millimeters.
a. if francine takes a full-length photograph of her friend from a distance of 3 meters
and the height of her friend is 140 centimeters, what will be the height of the image
on the film? (hint: convert to the same unit of measure.)
b. suppose the height of the image on the film of her friend is 15 millimeters. if
francine took a full-length shot, what was the distance between the camera and her
friend?

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .

all you should have to do is insert 1 where the c is, representing that one car is sold.

f(c) = 250c + 500

f(1) = 250(1) + 500

f(1) = 250 + 500

f(1) = 750

he earns $750 for each car sold.

hope this you! have a happy , here's a turkey!