What is the 22nd term of the arithmetic sequence 12, 17, 22, 27, …?

the 22nd term is 117

Step-by-step explanation:

The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first term of the sequence.

d represents the common difference between successive terms.

n represents the number of terms in the sequence.

From the information given,

a = 12

d = 17 - 12 = 22 - 17 = 27 - 22 = 5

n = 22

We want to determine the value of the 22nd, T22. Therefore,

T22 = 12 + (22 - 1)5

T22 = 12 + 105 = 117

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb