Motion and rate of change derivatives. attached is the question and where i am stuck, i would really appreciate the : )

  A.  3 < t < 9

Step-by-step explanation:

You have successfully found the values of t where the motion turns around (t=3 and t=10). Your knowledge of odd-degree polynomials tells you that the value of s(t) is decreasing for t < 3 (because the leading coefficient is negative), and is also decreasing for t > 10.

That is, the value of s(t) is increasing between t=3 and t=10, which means the particle is moving to the right in that interval. Since the function is only defined on the interval [0, 9] the particle is moving to the right on the interval (3, 9).

_____

At t=3 and t=10, the particle is stationary, moving neither right nor left.

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew

the correct answer is b. negative exponential growth.

step-by-step explanation:

you can tell it's an exponential function because it decreases rapidly then levels out and never touches the x-axis.

it is negative because the y-axis decreases as the x-axis increases.

therefore it is a negative exponential growth graph.

hope i !