Find three consecutive integers such that the product of the first and third is 5 greater than 5 times the second.

Step-by-step explanation:

3 consecutive integers

1st integer = x

2nd integer = x + 1

3rd integer = x + 2

the product of 1st and 3rd is 5 greater then 5 times the 2nd...

x(x+2) = 5(x + 1) + 5

x^2 + 2x = 5x + 5 + 5

x^2 + 2x = 5x + 10

x^2 + 2x - 5x - 10 = 0

x^2 - 3x - 10 = 0

(x - 5)(x + 2) = 0

x - 5 = 0             x + 2 = 0

x = 5                   x = -2

so it will be : 5,6,and 7     or -2,-1, and 0

$450.00 for 6 weeks

or

$300

step-by-step explanation:

$200.00 for first week $50.00 x5 equals $250 plus $200 equals $450.00 for six weeks.

$200 for first week

$200 x 0.10 = $20

$20 x 5 = $100

$200 + $100 = $300

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.