Arange of a set of numbers is 30. the highest number in the set is two tiples larger than the lowest number in the set. which
set of algebraic equations will solve for the highest and lowest numbers in the set?
a)
y - x = 30, y = 2x
b)
y + x = 30, y = 2x
2y - x= 30, 2x = y
2y + x = 30, 2x + y

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

1st, 348.600

2nd, 256.905

3rd, 892.500

4th, 6937

last one stays the same since it has no decimal

step-by-step explanation: