The perimeter of a parallelogram must be no less than 40 feet. the length of the rectangle is 6 feet. what are the possible measurements of the width? write an inequality to represent this problem. use w to represent the width of the parallelogram. [hint: the formula for finding the perimeter of a parallelogram is p = 2l + 2w. what is the smallest possible measurement of the width? justify your answer by showing all your work.

12 + 2w > 40

w > 19

Minimum value of w is 20 feet.

Step-by-step explanation:

If l is the length of the parallelogram and w is its width then the perimeter of the parallelogram will be given by P = 2l + 2w.

Now, given that l = 6 feet and P > 40 feet.

Hence, 2(6) + 2w > 40

⇒ 12 + 2w > 40

This is the required inequality.

Now, 2w > 38

⇒ w > 19 feet.

This is the measure of width (w) of the parallelogram.

Now, the smallest possible measurement of the width is 20 feet. (Answer)

replace   with   27   and simplify.

10 , 27 , 10 , 70 , 10 , 35 , 10 , 48

step-by-step explanation:

10 - 8 = -2

  8 - 6 = -2

etc, so -2 is the common difference

step-by-step explanation: