7x-5y=-15 and -14x+7y=0 solve by elimination

(5,10)

Step-by-step explanation:

multiply first equation with 2 and add it to second to eliminate X

7x-5y=-15  //*2

14x-10y=-30

-14x+7y=0

-3y=-30

y=-30/-3

y=10

7x=50-15

7x=35

x=35/7

x=5

answer: this is not a question

step-by-step explanation: this is a answer

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.