Given the graph of a scatterplot and a trend line, explain how you would find the equation of the trend line.

first of all, the trend line will be in the form of y = mx + c. ( where m = gradient of a line and c = y-intercept. )

secondly, extend the trend line to touch the y-axis and then read the value of where the line intersects the y-axis. from this you'll get the value of c.

finally take two coordinates from the

trend line and use the gradient formula. this will be the answer for getting m.

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.