there are 5 apples, 4 bananas, 6 oranges, and 5 peaches in a large bowl. if marie gets to pick twice and she keeps what she randomly selected, what is the probability that
she will pick a banana and then an orange?

6/95

Step-by-step explanation:

P(banana and then an orange)

= (4/20)(6/19)

= 6/95

Hence probability is 6/95

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8