Which is equivalent to rootindex 5 startroot 1,215 endroot superscript x?

243x
1,215 superscript one-fifth x
1,215 superscript startfraction 1 over 5 x endfraction
243 superscript startfraction 1 over x endfraction

1,215 Superscript one-fifth x

Step-by-step explanation:

Given:

The expression to simplify is given as:

We know that,

Here,

So,

So, the above expression becomes:

Now, using the law of indices

Here,

So, the expression is finally simplified to;

Therefore, the second option is the correct one.

= 1,215 Superscript one-fifth x

b. 1,215 Superscript one-fifth x

Step-by-step explanation:

1. 8

2. 9

3. 20

4. 3

5. 17

6. 2.2

7. 11.25

8. 1

9. 14

10. 2

step-by-step explanation:

thats the first half

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1