Solar panels use the suns energy to generate power. a town wants to install 28 solar panels in an array. what are all the possible ways the panels could be installed

The possible arrays are: (1,28) , (2,14) , (4,7)) , (7,4) , (14,2) and (28,1)

Step-by-step explanation:

Here, the total number of solar panels to be installed  = 28

Let  us assume the installed array has m rows and n columns.

Now, the total panels installed = Number of rows x Number of columns

or, 28 = m n

The following cases are possible for array:

(a) When  m = 1, n = 28  (as m x  n = 28)

So, here array has 1 row with 28 columns.

(b) When  m = 2, n = 14  (as m x  n = 28)

So, here array has 2 row with 14 columns.

(c) When  m = 4, n = 7  (as m x  n = 28)

So, here array has 4 row with 7 columns.

(d) When  m = 7, n = 4  (as m x  n = 28)

So, here array has 7 row with 4 columns.

(e) When  m = 14, n = 2  (as m x  n = 28)

So, here array has 14 row with 2 columns.

(f) When  m = 28, n = 1  (as m x  n = 28)

So, here array has 28 row with 1 columns.

s

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.