To rent a certain meeting room, a college charges a reservation fee of $15 and an additional fee of $4 per hour. the chemistry club wants to spend less than $43 on renting the room. what are the possible numbers of hours the chemistry club could rent the meeting room?

To rent a certain meeting room, a college charges a reservation fee of $31 and an additional fee of $5.90 per hour.

The chemistry club wants to spend less than $84.10 on renting the meeting room.

What are the possible amounts of time for which they could rent the meeting room?

Use t for the number of hours the meeting room is rented, and solve your inequality for t.

Your inequality is

31 + 5.9*t < 84.10.

To solve it, collect the constant terms on the right side:

5.9*t < 84.10 - 31 = 53.10,

Hence, t < 53.10%2F5.9 = 9 hours.

54

step-by-step explanation:

6x9

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step-by-step explanation: