Find the quadratic function ..

3x2 - y2 = 9

x2 + 2y2 = 38

Step-by-step explanation:

3x2 - y2 = 9(1)

x2 + 2y2 = 38(2)

Let x^2 = a and y^2 = b

:- the two equations becomes

3a - b = 9(3)

a + 2b = 38(4)

Multiplying (4) by 3

3a + 6b = 114(5)

Substracting (3) from (5)

3a - 3a + 6b - (-b) = 114 - 9

6b +b = 105

7b = 105

b = 105/7

b = 15

And 3a - b = 9 putting b = 15

3a - 15 = 9

3a = 15+9

3a = 24

a = 24/3

a = 8

And

x^2 = a

x^2 = 8

x = √8

x = √(4×2)

x = 2√2

Also y^2 = b

y^2 = 15

y = √15

56

step-by-step explanation:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐