Agardener is planting two types of trees:
type a is 7 feet tall and grows at a rate of 23 inches per year.
type b is 5 feet tall and grows at a rate of 25 inches per year.
algebraically determine exactly how many years it will take for these trees to be the
same height

It takes 12 years for both trees to be of same height

Solution:

Assume the year that it would take to these trees have the same height is : x (years)

Type A is 7 feet tall and grows at a rate of 23 inches per year:

Convert 7 feet to inches

We know that,

1 foot = 12 inch

7 feet = 12 x 7 inch = 84 inch

Thus, type A is 84 inches tall and grows at a rate of 23 inches per year

We can frame a equation as:

Type A = 84 + 23(number of years)

Type A = 84 + 23x eqn 1

Type B is 5 feet tall and grows at a rate of 25 inches per year

Convert 5 feet to inches

5 feet = 5 x 12 inches = 60 inches

Thus, type B is 60 inches tall and grows at a rate of 25 inches per year

We can frame a equation as:

Type B = 60 + 25(number of years)

Type B = 60 + 25x eqn 2

For both the trees to be of same height, eqn 1 must be equal to eqn 2

84 + 23x = 60 + 25x

25x - 23x = 84 - 60

2x = 24

x = 12

Thus it takes 12 years for both trees to be of same height

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step-by-step explanation:

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