Abasketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. she misses the first shot 40% of the time. when she misses the first shot, she misses the second shot 5% of the time.
part a: what is the probability of missing both free-throw shots?
part b: what is the probability of making at least 1 free-throw shot?

The probability of missing both free-throw shots = 2%

The probability of making at least 1 free-throw shot = 98%

Step-by-step explanation:

Given :

Probability that she misses the first shot  = 40%

Probability she misses the second shot  = 5%

Solution:

Part A: The probability of missing both free-throw shots:

The two shots are independent events so, we can use rule of independent events

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Part B: The probability of making at least 1 free-throw shot

Probability of making at least 1 free throw show shot = 1 - probability of miss both the shots

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b. 24 mm

step-by-step explanation:

use the pythagorean theorem.

a^2 + b^2 = c^2

a^2 + 7^2 = 25^2

a^2 + 49 = 625

a^2 = 576

a = 24

answer: b. 24 mm