When a ballplayer throws a ball straight up, by how much does the speed of the ball decrease each second while ascending? in the absence of air resistance, by how much does its peed increase each second while it is descending? how much time is required for its ascent as compared to its descent?

Step-by-step explanation:

We are in the case of vertical shot. If we neglect air resistance, the only force acting over the ball is gravity. As gravity acts down to earth and the ball is going up, speed´s ball  will be decreasing by gravity ( 9.8 m/sec²) That means the speed of the ball will be decreasing 9.8 m/sec, each second.

When the ball get the maximum height  Vy = 0 then the ball stars descending, and when the ball is descending again gravity is the only force acting gravity acts in the same direction as the ball´s movement, so the ball´s speed will increase at a rate of 9.8 m/sec  each second.

It is a well known fact that the time of the ball to get maximum height is the same as for the ball to fall down to earth. In other words time from the beginning of the movement up to maximum height is equal to time for the ball to fall down.

30 miles

step-by-step explanation:

we know that 60 seconds equals 1 minute and 60 minutes 1 hour

44 ft       60 sec     60 min     158400   ft

  *   *   =

1 sec       1 min       1 hour         hour

we know that there are 5280 ft per mile

158400   ft       1 mile         30 miles

  *   =

1   hour               5280 ft     1 hour

so in 1 hour   it can travel 30 miles