The ratio of the measures of the sides of a triangle is 3: 5: 7, and it's perimeter is 450 cm. find the measures of each side of the traiand it's perimeter is 450 cm. find the measures of each side of the triangle

The measures of each side of the triangle are 90cm, 150cm and 210cm

If the measures of the sides of a triangle is 3:5:7 and its perimeter is 450 cm, then the ratio of the sides will be:

3x:5x:7x

Taking the sum of the ratios and sum it to 450cm, wee will have;

3x + 5x + 7x  = 450

15x = 450

x = 450/15

x = 30

The first side = 3x = 3(30) = 90cm

Second sidee  = 5(30) = 150cm

Thirs side  = 7(30) = 210cm

Hence the measures of each side of the triangle are 90cm, 150cm and 210cm

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The answer to your question is 90 cm, 150 cm, 210 cm

Step-by-step explanation:

Data

Proportion      3 : 5 : 7

Perimeter        450 cm

Process

1.- Sum the proportions to find the total number of parts.

                     3 + 5 + 7 = 15 parts

2.- Divide the perimeter by the total number of parts

                     450 / 15 = 30

3.- Find the measure of the sides multiplying each ratio by the previous result

      Side 1 = 3(30) = 90 cm

      Side 2 = 5(30) = 150 cm

      Side 3 = 7(30) = 210 cm

answer

point o.

step-by-step explanation:

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

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5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.