What is the equation of the line that goes through the points (-5,-1) and (5,5)?

y = 3/5 x + 2.

Step-by-step explanation:

Use the point-slope equation of a straight line:

y - y1 = m (x - x1) where m = the slope amd (x1, y1) is a point on the line.

Here:

m = (5- (-1)) / (5 - (-5))

= 6/10

= 3/5.

Substituting for m and  (5, 5):

y - 5 = 3/5(x - 5)

y - 5 = 3/5x - 3

y = 3/5 x + 2.

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

125 yards

step-by-step explanation:

i take 75 plus 50.