Kristi had 12 jellybeans. one third of the jellybeans were red, and one sixth were green. what part of jelly beans were either red or green? this problem is about the fraction of a number. fist draw 12 jellybeans. color one third of them red and one sixth of them green. write and solve the problem.

1/2 of the jelly beans were either red or green.

Step-by-step explanation:

Of the 12 jellybeans, 1/3 were red, and 1/6 were green; this means the number of red jellybeans were

and the number of green jellybeans were

.

This means that we have 4+2=6 jellybeans that are either red or green. Now this 6 is

fraction of the total jelly beans.

Therefore 1/2 of the jellybeans were either red or green.

The appropriate number of red and green jellybeans are colored in the figure attached.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17