Faculty members at splitty town high school want to determine whether there are enough students to have a spring formal. seventy-two of the 225 students said they would attend the spring formal. construct and interpret a 95% confidence interval for p. a. the 95% confidence interval is (0.2591, 0.3810). there is a 95% chance that a randomly selected student who will attend the spring formal lies between 25.91% and 38.10%.b. the 95% confidence interval is (0.2591, 0.3810). ninety-five percent of all samples of this size will yield a confidence interval of (0.2591, 0.3810).c. the 95% confidence interval is (0.2591, 0.3810). we are 95% confident that the true proportion of students attending the spring formal is between 25.91% and 38.10%.d. the 95% confidence interval is (0.6190, 0.7410). ninety-five percent of all samples of this size will yield a confidence interval of (0.6190, 0.7410).e. the 95% confidence interval is (0.6190, 0.7410). we are 95% confident that the true proportion of students attending the spring formal is between 61.90% and 74.10%.

C. The 95% confidence interval is (0.2591, 0.3810). We are 95% confident that the true proportion of students attending the Spring Formal is between 25.91% and 38.10%.

Step-by-step explanation:

The interpretation of a confidence interval at a x% confidence level if that we are x% sure that the true proportion(mean) of the population is in this interval.

Confidence interval

In a sample with a number n of people surveyed with a probability of a success of , and a confidence interval , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of

For this problem, we have that:

Seventy-two of the 225 students said they would attend the Spring Formal. So

95% confidence interval

So , z is the value of Z that has a pvalue of , so .

The lower limit of this interval is:

The upper limit of this interval is:

The correct answer is:

C. The 95% confidence interval is (0.2591, 0.3810). We are 95% confident that the true proportion of students attending the Spring Formal is between 25.91% and 38.10%.

your answer would be 12

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step-by-step explanation: