A10 gallon aquarium is 3 inches higher than it is wide. its length is 21 inches and its volume is 2730 inches. what are the height and width of the aquarium?

The height and width of the aquarium are 13 inches and 10 inches respectively .

Step-by-step explanation:

Given : The volume of aquarium =  2730 cubic inches

Length of aquarium = 21 inches

Let x be the width of the aquarium,

then Height = x+3

We consider the shape of aquarium as cuboid.

Volume of Cuboid = Length x width x Height

Put values in the above formula , we get

So , the width of aquarium =x= 10 inches  ( width cannot be negative)

So height = 10+3=13 inches.

Hence, the height and width of the aquarium are 13 inches and 10 inches respectively .

37

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3