Let c be the circle |z| = r where r > 1. show that |[log z / z2 dz| < 2 pi pi + log r / r and hence that the value of the integral approaches zero as r tends to infinity.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

answerim :

n

step-by-step explanation:

im not sure but my dad knows