The rectangle shown has a perimeter of 58 cm and the given area. its length is 8 more than twice its width. write and solve a system of equations to find the dimensions of the rectangle. the area is 154cm squared

The length of the rectangle is 22 cm and width is 7 cm.

Step-by-step explanation:

Let the width of the rectangle be 'w'.

Given:

Perimeter (P) = 58 cm

Area of the rectangle (A) = 154 cm²

As per question:

Length = 8 more than twice its width

Now, perimeter is given as:

Now, we have to solve the given system of equations.

For that, we plug in 'L' from equation 1 to equation 2. This gives,

Therefore, the length of the rectangle is 22 cm and width is 7 cm.

Area = Length × Width = 22 × 7 = 154 cm².

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step-by-step explanation: