What is the horizontal asymptote of the function f (x) = startfraction (x minus 2) over (x minus 3) squared endfraction?

y=1

Step-by-step explanation:

See asymptote is a tangent to a function at infinity.

The function of x provided is

Now just roughly plot this function on graph by using these points mentioned.

Firstly x = 3 is not in domain of function because it's making denominator zero. Now if we calculate value of function around 3 then it tends to plus infinity.

If we move forward from 3 then value of function decreases from infinity and tends to 1.

Also  x = 2 is root of the function and behind 2 the function value increases and tend toward y =1.

Thus horizontal asymptote is y = 1.

b. an equilateral triangle inscribed in a circle

step-by-step explanation:

we are given the figure of two circles having a triangle inside.

now, we know that,

"when a figure is lying inside an another figure, then the outside figure is known as circumscribed figure and the figure lying inside is referred to as the inscribed figure".

as we see that, the circles are containing the triangle completely.

thus, the circles are the circumscribed figures and the triangle is the inscribed figure.

hence, we get, 'an equilateral triangle is inscribed in a circle'.

yes

step-by-step explanation: