Arectangle is three times as long as it is wide. if it's length and width are both decreased by 2 cm, it's area is decreased by 36 cm. find it's original dimensions

the original length of the rectangle is 15cm

the original width of the rectangle is 5 cm

Step-by-step explanation:

Let L represent the original length of the rectangle.

Let W represent the original width of the rectangle.

A rectangle is three times as long as it is wide. This means that

L = 3W

If it's length and width are both decreased by 2 cm, it's area is decreased by 36 cm. This

(L - 2)(W - 2) = LW - 36

LW - 2L - 2W + 4 = LW - 36

LW - LW - 2W - 2L = - 36 - 4

- 2L - 2W = - 40 - - - - - - - - - -1

Substituting L = 3W into equation 1, it becomes

- 2(3W) - 2W = - 40

- 6W - 2W = - 40

- 8W = - 40

W = - 40/- 8 = 5

L = 3W = 3 × 5 = 15

sss (side, side, side)

sas (side, angle, side)

asa (angle, side, angle)

aas (angle, angle, side)

hl (hypotenuse, leg)

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